When you access an element outside a container of the STL, the result is not so promising. You effect may be an error or undefined behaviour. Undefined behaviour means all bets are open.

First of all: What is a bounds error? A bounds error happens when you read or write beyond the elements of a container. The result is different depending on the used container. Of course, the C++ core guidelines is very concrete.
The C++ core guidelines starts with a bad example which uses the unsafe C-functions to fill and compare a std::array.
std::array<int, 10> a, b;
std::memset(a.data(), 0, 10); // BAD, and contains a length error (length = 10 * sizeof(int))
std::memcmp(a.data(), b.data(), 10); // BAD, and contains a length error (length = 10 * sizeof(int))
The comments to the code already say it. The length of the C-arrays is not 10 but 10 * sizeof(int). The solution is obvious. Use the functionality of the std::array.
std::array<int, 10> a;
std::array<int, 10> b;
std::array<int, 10> c{};
a.fill(0); // (1)
std::fill(b.begin(), b.end(), 0); // (2)
if ( a == b ){ // (3)
// ...
}
In this case, the std::array a and b are not initialised. In opposite, all values of c are initialised to 0. Line (1) sets all values of a to 0 and line 2 does the same by using the function templates std::fill. Comparison is also quite convenient (line 3).
Using a container outsides its range is in general undefined behaviour. Let me see what that means.
Bounds Errors
The most elementary sequential container we have in C++ is the C-array.
C-Array
The effect of an overflow or an underflow is the same: memory corruption and undefined behaviour. Let's make a simple test with an int array. How long will the next program run?
// overUnderflow.cpp
#include <cstddef>
#include <iostream>
int main(){
int a[0];
int n{};
while (true){
if (!(n % 100)){
std::cout << "a[" << n << "] = " << a[n] << ", a[" << -n << "] = " << a[-n] << "\n";
}
a[n] = n;
a[-n] = -n;
++n;
}
}
Way too long! The program writes each 100th array entry to std::cout.

Okay, what will happen if I use a sequential container from the STL? Here we are:
Sequential Containers of the STL
The index operator is available for std::array, std::vector, std::deque, and std::string. For simplicity reasons, I count a std::string as a sequential container. This means, all containers support random access and return a random access iterator. To bore you not to death I use in my next experiment only a std::array and a std::vector.
std::array
This is the modified program for std::array:
// overUnderflowStdArray.cpp
#include <array>
#include <iostream>
int main(){
std::array<int, 1> a;
int n{};
while (true){
if (!(n % 100)){
std::cout << "a[" << n << "] = " << a[n] <<
", a[" << -n << "] = " << a[-n] << "\n";
}
a[n] = n;
a[-n] = -n;
++n;
}
}
Using the index operator for a C++-array is not better than using it for a C-array.

Maybe, a std::vector comes to our rescue.
std::vector
// overUnderflowStdVector.cpp
#include <vector>
#include <iostream>
int main(){
std::vector<int> a{1};
int n{};
while (true){
if (!(n % 100)){
std::cout << "a[" << n << "] = " << a[n] <<
", a[" << -n << "] = " << a[-n] << "\n";
}
a[n] = n;
a[-n] = -n;
++n;
}
}
Because the std::vector creates its objects on the heap and not on the stack such as the C- and C++-array, it takes quite a while for the program to fail. The screenshots show the begin and the end of the under- and overflow.


Additionally, the associative containers such as std::map and std::unordered_map also support the index operator.
Associative Containers of the STL
What happens, when you use a non-existing key in a std::map or std::unordered_map?
// indexOperatorMapAndUnorderedMap.cpp
#include <iostream>
#include <map>
#include <unordered_map>
#include <string>
int main(){
std::cout << std::boolalpha << std::endl;
std::map<std::string, int> myMap;
std::unordered_map<std::string, bool> myUnorderedMap;
std::cout << "myMap[DoesNotExist]: " << myMap["DoesNotExist"] << std::endl;
std::cout << "myUnorderedMap[DoesNotExist]: " << myUnorderedMap["DoesNotExist"] << std::endl;
}
In case of the associative container, the value you get is well-defined if the key is not available. The value has to be DefaultConstructible because the default constructor is invoked if the key is not available. This creates der literal 0 in the first case and the literal false in the second case.

Okay, the essential question of the guideline remains: How can you avoid bounds errors?
Avoid bounds errors
In case of the C-array there is no rescue to detect a bounds error. For the C++ containers including std::string there is the method at which checks the bounds. All C++ container throw a std::out_of_range exception if you access a non-exsiting element of the container. The std::string shows this impressive.
// stringBoundsCheck.cpp
#include <stdexcept>
#include <iostream>
#include <string>
int main(){
std::cout << std::endl;
std::string str("1123456789");
str.at(0) = '0'; // (1)
std::cout << str << std::endl;
std::cout << "str.size(): " << str.size() << '\n';
std::cout << "str.capacity() = " << str.capacity() << '\n';
try {
str.at(12) = 'X'; // (2)
}
catch (const std::out_of_range& exc) {
std::cout << exc.what() << std::endl;
}
std::cout << std::endl;
}
Setting the first character of the string str to '0' (line 1) is fine, but accessing a character outside the size is an error. This even holds if the access is within the capacity but outside the size of the std::string.
- The size of a std::string is the number of elements the std::string has.
- The capacity of a std::string is the number of elements a std::string could have without allocating additional memory.
The error message of the windows compiler 19.20 is unspecific.

The error message for the GCC 8.2 is quite specific.

What's next?
This post was the last one to the containers of the STL. The next post is about the various string types.
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